標題: 非圓齒輪二次開發(fā) [打印本頁] 作者: lijun1226 時間: 2016-7-8 16:10 標題: 非圓齒輪二次開發(fā) 畫齒廓,，為什么最高點不在齒頂高那里,。感覺不對。大家能看看我的程序嗎,？Dim i As Integer N. _9 \0 n, ]8 F: q" g$ g
ReDim x0(18) , t3 _! l& b; |& y2 M/ F& F) l" kReDim y0(18)+ \8 Z' t9 `9 X" b
9 L4 c1 D) h! M7 i+ {9 DDim k0 As Integer ! w7 I* ]' @% V9 T& v! MReDim p0(18)# u2 R4 c& D9 K; B6 f& ^( ]
ReDim q0(18)1 R! c( ^: x; y1 u8 D6 b2 M
[* p( f {! G
Dim h0 As Integer & Q& u$ X& l }3 s% IReDim p00(18)7 ~ |( c. X! G8 S' J9 u
ReDim q00(18) }8 E, a2 b+ s1 a. u2 H' n
( |2 `. B3 @" c) G3 G9 [" f2 z4 Q, e5 K; D
u = Sqr((Da / Db) ^ 2 - 1)+ V. D* ~1 j; k! x1 X7 N$ M2 u
g = u / 14 K3 ^1 B) F7 N# v) W. h" n r) b! G
9 L: X+ I) N" r) I( K- E
xx = 0.5 * Da * Sin(Tan(f) - f) |/ l' V6 J5 P+ d$ \yy = 0.5 * Da * Cos(Tan(f) - f)# n" P" q8 y& M6 c
0 F6 D/ M& A( M& c( t2 Z2 [ . y, [! x' p' S) r& X! x; F! b! [$ A2 R; P2 u: X Y
3 c; T, m" o+ n" v' Ns = pi * m / 2 6 C% ~0 r1 [4 M% u' d* I' Cinva = Tan(a) - a% c$ N2 \2 i( U( z2 ]6 c- _ m9 g
sb = Cos(a) * (s + m * z * inva) + V: X& a6 `) U& N [j = 2 * sb / Db, h$ D! a" W& e! Y& N9 N2 T, A
- p7 r6 Y6 y) s) ^
t = 0 * Q- c* J) [, a. P7 ]% J 8 v; d t6 X! x: t D* j4 y vFor i = 1 To 14 1 q, d- U4 t( `2 e0 w- D. [ k* X% F- @
If t <= u Then e/ ^# r% J- i* d! V6 i . U' [, p; M. o7 ex0(i) = 0.5 * Db * Sin(t) - Db / 2 * t * Cos(t) 2 e! X* `0 o; {+ V* c8 yy0(i) = 0.5 * Db * Cos(t) + Db / 2 * t * Sin(t) v( H& _% P6 o, ]; O2 J# Y1 t# o
# v1 O0 h" o) }; Y+ Fp00(i) = -0.5 * Db * Sin(t) + 0.5 * Db * t * Cos(t)! {! E2 j& ?: J. V" V
q00(i) = 0.5 * Db * Cos(t) + 0.5 * Db * t * Sin(t)* u; q8 B3 X( R: Y- P: \5 a- H$ M
' L9 K1 Q* ^( H6 r4 N( Q/ \& S; It = t + g 9 \$ Q! R3 x+ ^1 g 9 K0 L4 \( ~# i) R/ }% cp0(i) = p00(i) * Cos(j) + q00(i) * Sin(j)( g5 t# Z. s7 }5 @
q0(i) = -p00(i) * Sin(j) + q00(i) * Cos(j) 3 F0 ]. a) n. q/ F q: l: MEnd If 2 c* P$ b$ A, N( gNext i2 H7 z/ |; ?2 a' C2 ~$ R$ U* O
1 I9 Q& H" y# c: H9 [. @Part.SetPickMode5 q) i, W+ O3 a( ?) u
xx = 0 / \& B" M8 s. f- ]1 Y+ F( xyy = 0.5 * Df. q) F; l' Q8 ]7 ~
Xx1 = xx * Cos(j) + yy * Sin(j) u) V! q+ h& u3 m& S. FYy1 = xx * Sin(j) + yy * Cos(j)8 K j3 {, g3 h+ X
, [- @# E+ ^9 t( B' H: d0 p
p000 = -0.5 * Db * Sin(0) + 0.5 * Db * 0 * Cos(0)- [+ ~4 L4 B; Q7 x: M
q000 = 0.5 * Db * Cos(0) + 0.5 * Db * 0 * Sin(0), ?+ X1 Q3 ^( H* A# E& ~5 F