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21#
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發(fā)表于 2009-4-12 10:49:43
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Can I convert points of a plane into individual points
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0 ~0 O* I: {' r j' t) ~) r: c! t我能從多點(diǎn)組成的面中分離出單獨(dú)的點(diǎn)嗎?
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I'm sorry, I have not played around to find out for myself due to work load but, I have a disc with 20 pockets, each pocket has 3 recesses. I need to check / B" H/ a4 `* G, I, b; _8 A6 Q
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the "Z" distance between 2 planes and since I need to referance / align each plane later in the PPG, it would be much easier to pull 1, 5 points out from the
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plane and call it an individual point to get my "Z" distance. I can not due a loop due to each point and plane needs a seperate name and for the scientists ( H4 }( o, Y. x) @+ P
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to be able to figure out the CMM output easily and at the bottom of each pocket I take 25 pt's so tghey can determin contour of each pocket.* t, C: ]5 @4 E) D" }) d% C N
* j% X$ [9 ]: C( G1 B2 D+ t; q3 T對不起,我不是為了好玩而是真的工作需要,,我有一個(gè)圓盤工件,上面分布20個(gè)輪廓,,每個(gè)輪廓有3個(gè)凸行,。 我需要檢查兩個(gè)面之間的z軸距離.在工件坐標(biāo)系中需要整理每一個(gè)面,,
! M, O% N8 O$ H3 D- ~$ }這將很容易將 1, 5 點(diǎn)分離出,同時(shí)調(diào)出一個(gè)單獨(dú)的點(diǎn)坐標(biāo)就可以得到我的z軸距離.我不能得到一個(gè)循環(huán)是因?yàn)槊恳粋(gè)點(diǎn)和面都需要一個(gè)獨(dú)立的名字.為了cmm更容易的輸出科學(xué)的計(jì)
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c2 I- W; M1 {" W: u算值.在每個(gè)孔的地步我取了25個(gè)點(diǎn)以描述每個(gè)圓輪廓
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' H5 [% W i/ w8 E$ |why don't you measure as points, then you can connect the sets of points together as planes, but you will still have the points to do any further analysis ) G7 w2 P- A+ f& \
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with 8 U2 V, c w$ o& ?" E
3 p# b3 H: h, E1 T為什么你不測量點(diǎn)要素,然后你可以將點(diǎn)云組合成平面,,同時(shí)你依然擁有點(diǎn)要素做進(jìn)一步的分析
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Thanks for the input, I've done that before but just thought I could grab a point of a plane rather than having to manually take my plane points.
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6 o, f$ v" A0 l% H謝謝回復(fù),,我已經(jīng)那樣做了, 但是我想能不能從平面上抓一點(diǎn),而不是想手動的測量平面點(diǎn).
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+ c/ A0 T. w9 E1 d* t+ HIf you have measured the plane(s) as auto planes, then you can get hold of the individual measured points using the formula calculation tokens# @# C& x. C& w+ v% D
- for example 'PL[1].MP[1].X' would return the value in X of the first point in plane memory 1. So you could just process a simple loop after the measurement . b. V0 X5 |4 V, D
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of each plane to grab hold of the X,Y & Z vals of each point and transfer them into individual element points.' P4 u, }* E, T+ q# |7 x
Be aware that the points are uncompensated. I have attempted to attach the example prog (.CAB and ._PI files) which you can import from the part manager
! U8 n& E1 e2 z8 B/ WClick here for plane points._PI . A2 y/ R/ P0 ?
0 d& _# u0 [0 W如果你已經(jīng)測量平面為自動平面,那么你能得到一個(gè)單獨(dú)的點(diǎn)通過變量計(jì)算
) Q* ]7 h4 A9 a7 E- 舉例來說 'PL[1].MP[1].X'將會返回平面第一個(gè)點(diǎn)的x軸坐標(biāo)值. 因此你僅僅需要做一個(gè)簡單的循環(huán)從每一個(gè)面的測量結(jié)果中分離出它每一個(gè)點(diǎn)的xyz坐標(biāo)值.然后把他們組合成% }9 \# }, p( i! Y
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一個(gè)個(gè)單獨(dú)的點(diǎn)要素
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5 y9 v9 j* ~" a0 O+ Y' n8 u" W注意,,這些點(diǎn)是沒有探針補(bǔ)償,。 我已經(jīng)嘗試附上一個(gè)程序例子(.CAB and ._PI files),你可以從程序入口導(dǎo)入
& `7 f8 {2 k3 E) \+ h# T1 T& [- Q點(diǎn)擊這里為了平面點(diǎn)。_PI
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. L) {" H. y/ c mflyfish - send me your email and I will send the program to you
; D" n0 E. I: X- [1 ]' F1 nflyfish -把你的電子郵件發(fā)給我和我把程序發(fā)給你
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' x4 r1 e- [* {1 M. ?& N7 s$ x1 MWhen you grab the points in formula calculation, you should be able to
- r, P3 z# Z) [also deduct the probe radius result to equate to a compensaed point.
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Obviously only if you probed perpendicular to the surface. . . I think .
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當(dāng)你抓取測量點(diǎn)的時(shí)候,,你同樣能夠到也減去探針半徑值得到一個(gè)無補(bǔ)償點(diǎn),。
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當(dāng)然如果你的探針運(yùn)動軌跡垂直與工件表面... 我個(gè)人看法。 |
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