非圓齒輪二次開發(fā)

lijun1226

畫齒廓,，為什么最高點不在齒頂高那里,。感覺不對,。大家能看看我的程序嗎,？Dim i As Integer
ReDim x0(18)
ReDim y0(18)

" @3 ]- H+ G& N; L" }( ZDim k0 As Integer
ReDim p0(18)
. F" |( w- ^- Y* l/ ]6 EReDim q0(18)

Dim h0 As Integer
' Q' p4 g! V- k3 _  U. h$ }ReDim p00(18)
5 ?" m: x' J) h" p) d% |ReDim q00(18)

+ n8 t, U- C& B! v7 ~5 y' Q% t9 B
+ \* W# a9 U% X$ g+ Y" y& Au = Sqr((Da / Db) ^ 2 - 1)
% y  y  j( E6 Ng = u / 14
( \9 O9 r" Z7 C; B

9 j5 {2 R+ c5 [/ Bxx = 0.5 * Da * Sin(Tan(f) - f)
4 Y3 q  B# e. b9 A4 b- gyy = 0.5 * Da * Cos(Tan(f) - f)

  D% N$ g3 n4 K4 D
3 i$ T  Y) u% R5 S* h
. a/ D6 B9 A; y' e
s = pi * m / 2
9 N) ~9 B" x. J( x" N3 Dinva = Tan(a) - a
sb = Cos(a) * (s + m * z * inva)
1 F( \' `, x" H$ `j = 2 * sb / Db

6 b+ n3 ^0 A- i4 d  [t = 0
3 u% Z! k9 c! C
For i = 1 To 14
8 |  d% Z0 N1 Y, P9 R* M
. \/ t8 r+ I3 ~* d6 n+ u9 f( mIf t <= u Then

; n; x9 b; U$ K# ~* o" ^3 t) U) ]x0(i) = 0.5 * Db * Sin(t) - Db / 2 * t * Cos(t)
+ Y* Q8 q8 T0 O/ ^% `y0(i) = 0.5 * Db * Cos(t) + Db / 2 * t * Sin(t)
+ \! E& E  R4 e' K
1 z: ?2 \9 u4 H# e/ Gp00(i) = -0.5 * Db * Sin(t) + 0.5 * Db * t * Cos(t)
# A: _# T; ?* V, ?- _q00(i) = 0.5 * Db * Cos(t) + 0.5 * Db * t * Sin(t)

* F& }* r- b2 ]) X6 i/ E( xt = t + g

p0(i) = p00(i) * Cos(j) + q00(i) * Sin(j)
q0(i) = -p00(i) * Sin(j) + q00(i) * Cos(j)
End If
Next i

1 _1 ]6 m4 D+ e# N" R( R! aPart.SetPickMode
$ ]( p$ ^) v& r) hxx = 0
yy = 0.5 * Df
( u0 c9 v- T" y/ x4 X- f9 KXx1 = xx * Cos(j) + yy * Sin(j)
/ z! O0 o6 V/ b; w7 Q6 ^* S/ |5 pYy1 = xx * Sin(j) + yy * Cos(j)

. n5 X5 O6 D" hp000 = -0.5 * Db * Sin(0) + 0.5 * Db * 0 * Cos(0)
q000 = 0.5 * Db * Cos(0) + 0.5 * Db * 0 * Sin(0)
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. K' u7 W/ M. G! S. \
Part.SketchSpline 13, 0.001 * x0(1), 0.001 * y0(1), 0
Part.SketchSpline 12, 0.001 * x0(2), 0.001 * y0(2), 0
Part.SketchSpline 11, 0.001 * x0(3), 0.001 * y0(3), 0
, n, r' j/ B$ d6 u% N: RPart.SketchSpline 10, 0.001 * x0(4), 0.001 * y0(4), 0
, R. n$ q" [) m3 |Part.SketchSpline 9, 0.001 * x0(5), 0.001 * y0(5), 0
. i( A4 j( Q0 _' v1 cPart.SketchSpline 8, 0.001 * x0(6), 0.001 * y0(6), 0
5 ~# [) |8 x3 O' z, JPart.SketchSpline 7, 0.001 * x0(7), 0.001 * y0(7), 0
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Part.SketchSpline 6, 0.001 * x0(8), 0.001 * y0(8), 0
Part.SketchSpline 5, 0.001 * x0(9), 0.001 * y0(9), 0
2 P! G/ H% E( d- T8 H; `& E& OPart.SketchSpline 4, 0.001 * x0(10), 0.001 * y0(10), 0
Part.SketchSpline 3, 0.001 * x0(11), 0.001 * y0(11), 0
0 [1 Y( V4 u  Q9 Q& ePart.SketchSpline 2, 0.001 * x0(12), 0.001 * y0(12), 0
/ Q# f+ y. S& L% G! {0 |' |2 ~Part.SketchSpline 1, 0.001 * x0(13), 0.001 * y0(13), 0
" ^' F" N3 y/ gPart.SketchSpline 0, 0.001 * x0(14), 0.001 * y0(14), 0
: _5 p, V8 j) t0 g) z

7 p$ @, a: Z* y5 \, P, fPart.SketchSpline 13, 0.001 * p0(1), 0.001 * q0(1), 0
2 F  g/ c8 D9 Q+ VPart.SketchSpline 12, 0.001 * p0(2), 0.001 * q0(2), 0
Part.SketchSpline 11, 0.001 * p0(3), 0.001 * q0(3), 0
  o! M2 U- h* Q5 i4 X6 L- F2 YPart.SketchSpline 10, 0.001 * p0(4), 0.001 * q0(4), 0
Part.SketchSpline 9, 0.001 * p0(5), 0.001 * q0(5), 0
Part.SketchSpline 8, 0.001 * p0(6), 0.001 * q0(6), 0
Part.SketchSpline 7, 0.001 * p0(7), 0.001 * q0(7), 0
) w* x3 t$ y" R3 I6 N7 h9 Q* J
Part.SketchSpline 6, 0.001 * p0(8), 0.001 * q0(8), 0
Part.SketchSpline 5, 0.001 * p0(9), 0.001 * q0(9), 0
/ @! v! @/ W' j" BPart.SketchSpline 4, 0.001 * p0(10), 0.001 * q0(10), 0
Part.SketchSpline 3, 0.001 * p0(11), 0.001 * q0(11), 0
4 z5 U+ g  h2 Z/ w) h# iPart.SketchSpline 2, 0.001 * p0(12), 0.001 * q0(12), 0
Part.SketchSpline 1, 0.001 * p0(13), 0.001 * q0(13), 0
Part.SketchSpline 0, 0.001 * p0(14), 0.001 * q0(14), 0

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George_W4TBo

是solidworks的二開嗎,，真費勁哥都比較擯棄，這是最近做的一個單邊連續(xù),，單邊步進機構(gòu)的其中一對非圓齒輪,，在家里所以圖不多，有空再更新,，歡迎交流