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21#
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發(fā)表于 2009-4-12 10:49:43
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Can I convert points of a plane into individual points * L" F/ L" {" u/ v" K
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我能從多點(diǎn)組成的面中分離出單獨(dú)的點(diǎn)嗎?1 _, x. }1 c' f. q+ F
8 q) v7 l1 V" w1 tI'm sorry, I have not played around to find out for myself due to work load but, I have a disc with 20 pockets, each pocket has 3 recesses. I need to check
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the "Z" distance between 2 planes and since I need to referance / align each plane later in the PPG, it would be much easier to pull 1, 5 points out from the ; J" d" Z$ a3 x5 Q' S
' y8 x/ f* E/ j7 U9 rplane and call it an individual point to get my "Z" distance. I can not due a loop due to each point and plane needs a seperate name and for the scientists
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to be able to figure out the CMM output easily and at the bottom of each pocket I take 25 pt's so tghey can determin contour of each pocket.
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- L* U7 C8 I# d對(duì)不起,我不是為了好玩而是真的工作需要,,我有一個(gè)圓盤(pán)工件,上面分布20個(gè)輪廓,,每個(gè)輪廓有3個(gè)凸行,。 我需要檢查兩個(gè)面之間的z軸距離.在工件坐標(biāo)系中需要整理每一個(gè)面,,
& q4 \% v9 u$ r6 u: S2 D+ {. d這將很容易將 1, 5 點(diǎn)分離出,同時(shí)調(diào)出一個(gè)單獨(dú)的點(diǎn)坐標(biāo)就可以得到我的z軸距離.我不能得到一個(gè)循環(huán)是因?yàn)槊恳粋(gè)點(diǎn)和面都需要一個(gè)獨(dú)立的名字.為了cmm更容易的輸出科學(xué)的計(jì)
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算值.在每個(gè)孔的地步我取了25個(gè)點(diǎn)以描述每個(gè)圓輪廓, c* x1 _2 U& F1 j
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why don't you measure as points, then you can connect the sets of points together as planes, but you will still have the points to do any further analysis 2 l" W! y. t/ C, _8 ~& j
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; A X* n: {3 c2 X( |, Y為什么你不測(cè)量點(diǎn)要素,,然后你可以將點(diǎn)云組合成平面,同時(shí)你依然擁有點(diǎn)要素做進(jìn)一步的分析
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Thanks for the input, I've done that before but just thought I could grab a point of a plane rather than having to manually take my plane points.& @) L! [2 c+ d5 V* N
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謝謝回復(fù),,我已經(jīng)那樣做了, 但是我想能不能從平面上抓一點(diǎn),而不是想手動(dòng)的測(cè)量平面點(diǎn).
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; f) V2 K1 [, a( i$ P7 s# ^If you have measured the plane(s) as auto planes, then you can get hold of the individual measured points using the formula calculation tokens5 M5 \$ N3 V, [: M2 J+ _
- for example 'PL[1].MP[1].X' would return the value in X of the first point in plane memory 1. So you could just process a simple loop after the measurement
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1 _8 ^9 @" k" Q Mof each plane to grab hold of the X,Y & Z vals of each point and transfer them into individual element points.
: @% p2 m) k. m& @) {0 vBe aware that the points are uncompensated. I have attempted to attach the example prog (.CAB and ._PI files) which you can import from the part manager& G% M& ]& @& l3 a" R3 p
Click here for plane points._PI
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如果你已經(jīng)測(cè)量平面為自動(dòng)平面,,那么你能得到一個(gè)單獨(dú)的點(diǎn)通過(guò)變量計(jì)算
# x4 X% { W; O1 b- 舉例來(lái)說(shuō) 'PL[1].MP[1].X'將會(huì)返回平面第一個(gè)點(diǎn)的x軸坐標(biāo)值. 因此你僅僅需要做一個(gè)簡(jiǎn)單的循環(huán)從每一個(gè)面的測(cè)量結(jié)果中分離出它每一個(gè)點(diǎn)的xyz坐標(biāo)值.然后把他們組合成
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一個(gè)個(gè)單獨(dú)的點(diǎn)要素
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! @: T0 Y$ K3 }7 ?3 Q Q注意,這些點(diǎn)是沒(méi)有探針補(bǔ)償,。 我已經(jīng)嘗試附上一個(gè)程序例子(.CAB and ._PI files),你可以從程序入口導(dǎo)入, q5 E9 |9 Y* v1 A1 Q
點(diǎn)擊這里為了平面點(diǎn),。_PI ! @" h3 p5 }2 Q8 o* E! j$ j
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# z' [* u: X+ d+ A, @flyfish - send me your email and I will send the program to you 5 f; L: i" D6 c# ~, n, I2 t
flyfish -把你的電子郵件發(fā)給我和我把程序發(fā)給你
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When you grab the points in formula calculation, you should be able to
" p3 z3 l. Z# e+ V! ?9 Q/ b! dalso deduct the probe radius result to equate to a compensaed point.
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Obviously only if you probed perpendicular to the surface. . . I think .
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當(dāng)你抓取測(cè)量點(diǎn)的時(shí)候,你同樣能夠到也減去探針半徑值得到一個(gè)無(wú)補(bǔ)償點(diǎn),。* A, s% @7 |4 p2 G+ B
1 m5 r' k" m2 n" H4 E當(dāng)然如果你的探針運(yùn)動(dòng)軌跡垂直與工件表面... 我個(gè)人看法,。 |
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