本人的畢業(yè)設計：關于UG的二次開發(fā)運用（GRIP語言編程）

fewofj

) t6 ]* `$ B" c# K* ?0 J& `
下面是關于凸輪的一個運動軌跡的編程，只要把程序?qū)�入到UG中就可以實現(xiàn)凸輪的運轉(zhuǎn),，還可以修改程序中各個凸輪的參數(shù)來實現(xiàn)各種凸輪的運轉(zhuǎn),。組合運動規(guī)律
ENTITY/pt(360),spln(4),PT1,CR1,CR2,ext
NUMBER/J(360),S(360),X(360),Y(360),i,m,e,n
5 k3 a# N  Q. W. o& h# aDATA/i,1,m,1,e,1,n,1  $$賦值
) B$ f% \7 A- h8 I7 @l30:
! @' c* o* M( d; J  D. @2 pPARAM/'凸輪參數(shù)',$
2 B* h; _0 q; @( x# |'升程（h）',h,$
( C' g4 G: r) P, V& F' b8 |'基圓半徑（R0）',R0,$
$ ]8 D; ~; }  t2 e'滾子半徑（Rr）',Rr,$
. O/ o' R  ~# r% H8 [- v'推程轉(zhuǎn)角（Angle1）',Angle1,$
'遠休止角（Angle2）',Angle2,$
$ B' @+ ^' p  Y4 w0 k'回程轉(zhuǎn)角（Angle3）',Angle3,$
'近休止角（Angle4）',Angle4,$
respond
JUMP/l30:,stop:,,respond
MESSG/'您已輸入完參數(shù),！'
l00:
CHOOSE/'選擇推程運動規(guī)律',$
'一次多項式推程','二次多項式推程','五次多項式推程',$
'簡諧運動推程','擺線運動推程',$
DEFLT,1,respond
JUMP/l00:,stop:,,,lab1:,lab2:,lab3:,lab4:,lab5:,respond
, s9 k' L2 e' El20:
1 p) \# b$ w1 w9 ]4 e6 [) h) fCHOOSE/'選擇回程運動規(guī)律',$
'一次多項式回程','二次多項式回程','五次多項式回程',$
'簡諧運動回程','擺線運動回程',$
DEFLT,1,respond
JUMP/l20:,stop:,,,lab6:,lab7:,lab8:,lab9:,lab10:,respond
lab1:
MESSG/'一次多項式推程'
* `3 {9 W/ J6 r9 ?LAA:
IFTHEN/i<Angle1+2
* p# Z$ ~! }. A" CJ(i)=i-1
4 m; Q) ]/ y+ y5 i4 Q" GS(i)=h*J(i)/Angle1
+ ^; N3 p- ?) S" `% PX(i)=(R0+S(i))*cosf(J(i))
# ]' J% I: ?, ~  ZY(i)=(R0+S(i))*sinf(J(i))
Z=0
pt(i)=POINT/X(i),Y(i),Z
i=i+1
JUMP/LAA:
: k! H+ @5 i- [ENDIF
spln(1)=SPLINE/pt(1..Angle1+1)
DELETE/pt(1..Angle1+1)
JUMP/l20:
lab2:
MESSG/'二次多項式推程'
* b- j4 m+ g. q' E' i' ?% L4 V$$推程等加速階段
LBB:
IFTHEN/i<Angle1/2+2
6 X8 C9 o( I# T2 C+ x- _J(i)=i-1
/ T* v' B0 x6 LS(i)=2*h*J(i)*J(i)/(Angle1*Angle1)
X(i)=(R0+S(i))*cosf(J(i))
Y(i)=(R0+S(i))*sinf(J(i))
Z=0
1 O( S! g; @, w3 |  J( a* qpt(i)=POINT/X(i),Y(i),Z
i=i+1
JUMP/LBB:
ENDIF
5 c/ t- B1 D! b% Y2 @. @spln(1)=SPLINE/pt(1..Angle1/2+1)
DELETE/pt(1..Angle1/2+1)
$$推程等減速階段
LCC:
! @' ~9 x7 S  J0 z$ cIFTHEN/e<Angle1/2+2
J(e)=e+Angle1/2-1
5 J! Y5 k+ z- q# gS(e)=h-2*h*(Angle1-J(e))*(Angle1-J(e))/(Angle1*Angle1)
X(e)=(R0+S(e))*cosf(J(e))
# c2 z- M1 D& _Y(e)=(R0+S(e))*sinf(J(e))
Z=0
pt(e)=POINT/X(e),Y(e),Z
e=e+1
: U$ p' D9 f' JJUMP/LCC:
3 @/ L& N& C+ H! \7 [  }ENDIF
, t" g. c: G; T1 \3 Mspln(2)=SPLINE/pt(1..Angle1/2+1)
6 S/ r/ X& g% K1 }DELETE/pt(1..Angle1/2+1)
JUMP/l20:
lab3:
( _) b- M/ H% V+ |3 H! QMESSG/'五次多項式推程'
4 L. M0 C  L9 R" ^# O# lLDD:
IFTHEN/i<Angle1+2
& h1 z- _- k( ]. K$ k( t  TJ(i)=i-1
Q=J(i)/Angle1
  Q5 u. N2 J' E: s2 vS(i)=h*(10*Q*Q*Q-15*Q*Q*Q*Q+6*Q*Q*Q*Q*Q)
  B; M5 S0 E- v+ S. a- f9 x9 zX(i)=(R0+S(i))*cosf(J(i))
Y(i)=(R0+S(i))*sinf(J(i))
Z=0
) _$ i& h: W. V% y7 B; \# k# b! ypt(i)=POINT/X(i),Y(i),Z
i=i+1
JUMP/LDD:
ENDIF
( W" T) [# ]5 aspln(1)=SPLINE/pt(1..Angle1+1)
DELETE/pt(1..Angle1+1)
/ }. K& E3 J, RJUMP/l20:
lab4:
MESSG/'簡諧運動推程'
LEE:
IFTHEN/i<Angle1+2
' x1 @+ u4 K' J. i! {) {# J- c$ ~J(i)=i-1
$ m' Y2 R: D$ i% `# D. b4 OS(i)=h*(1-cosf(180*J(i)/Angle1))/2
$ W5 T5 D* h1 sX(i)=(R0+S(i))*cosf(J(i))
Y(i)=(R0+S(i))*sinf(J(i))
4 w4 m8 b5 q7 t4 TZ=0
2 X, ~/ [: M8 A! {* C4 ^( E! ]pt(i)=POINT/X(i),Y(i),Z
$ s5 N# |- A+ M9 [) [i=i+1
JUMP/LEE:
7 `# A4 U% q2 A$ vENDIF
spln(1)=SPLINE/pt(1..Angle1+1)
+ W) {2 X& O0 k8 KDELETE/pt(1..Angle1+1)
+ t8 N, b; D( R: KJUMP/l20:
/ _6 N$ t% }4 [0 V% p7 xlab5:
MESSG/'擺線運動推程'
LFF:
; `( m# b$ F9 Q; I, ~IFTHEN/i<Angle1+2
: b$ N+ X# X5 G3 ~8 }4 V7 t3 PJ(i)=i-1
S(i)=h*(J(i)/Angle1-sinf(360*J(i)/Angle1)/6.2832)
X(i)=(R0+S(i))*cosf(J(i))
) o3 w" J+ i8 b) }: I2 S0 U; FY(i)=(R0+S(i))*sinf(J(i))
- P' J: Q! Y# U* F4 ^3 h6 j% ]Z=0
pt(i)=POINT/X(i),Y(i),Z
i=i+1
$ m; `5 u1 v1 C0 P' S/ UJUMP/LFF:
ENDIF
spln(1)=SPLINE/pt(1..Angle1+1)
% S4 s* X5 N1 \) N- x* qDELETE/pt(1..Angle1+1)
JUMP/l20:
lab6:
MESSG/'一次多項式回程'
. J  I, }2 Q( ?; p( e: bLHH:
IFTHEN/m<Angle3+2
( Q; ]) `, c; P: d2 r4 |- u3 g0 NJ(m)=m+Angle1+Angle2-1
+ L4 K; h0 C4 c; n; U3 TS(m)=h-h*(J(m)-Angle1-Angle2)/Angle3
X(m)=(R0+S(m))*cosf(J(m))
! |- v' {) V) r( [" pY(m)=(R0+S(m))*sinf(J(m))
Z=0
pt(m)=POINT/X(m),Y(m),Z
m=m+1
JUMP/LHH:
ENDIF
+ y6 f$ Y; Y$ v' T  ?, U) Cspln(2)=SPLINE/pt(1..Angle3+1)
DELETE/pt(1..Angle3+1)
JUMP/l40:
lab7:
# Z* M' H  n7 c7 z: Z2 sMESSG/'二次多項式回程'
' ~) o; ?$ g) e) T1 |$$回程等減速階段
LII:
7 X) b0 h# e# m2 y3 A- I! z# ~  \IFTHEN/m<Angle3/2+2
J(m)=m+Angle1+Angle2-1
5 n) M1 y' v7 Y1 E/ g# ?S(m)=h-2*h*(J(m)-Angle1-Angle2)*(J(m)-Angle1-Angle2)/(Angle3*Angle3)
X(m)=(R0+S(m))*cosf(J(m))
Y(m)=(R0+S(m))*sinf(J(m))
Z=0
4 [" k8 Z1 o# Gpt(m)=POINT/X(m),Y(m),Z
m=m+1
JUMP/LII:
/ v1 r: U% t: |+ v& t3 n3 Y& U; iENDIF
$ [9 F! J4 R) m% t+ P5 ]spln(3)=SPLINE/pt(1..Angle3/2+1)
* B  a4 N% c2 Y8 v+ Q7 \DELETE/pt(1..Angle3/2+1)
$$回程等加速階段
LKK:
IFTHEN/n<Angle3/2+2
" z- x2 e& p) f( n- m' ^& l$ [J(n)=n+Angle1+Angle2+Angle3/2-1
Q=Angle1+Angle2+Angle3
6 A4 G$ z: K+ d% `) E+ hS(n)=2*h*(Q-J(n))*(Q-J(n))/(Angle3*Angle3)
) L' N% z8 G. Z/ @X(n)=(R0+S(n))*cosf(J(n))
Y(n)=(R0+S(n))*sinf(J(n))
Z=0
pt(n)=POINT/X(n),Y(n),Z
$ C/ I1 i5 V* j/ R3 T# w" Fn=n+1
JUMP/LKK:
ENDIF
- |+ W& C" ?# |0 `6 j0 L- k$ mspln(4)=SPLINE/pt(1..Angle3/2+1)
/ G3 I2 `7 ~7 B; A4 yDELETE/pt(1..Angle3/2+1)
: K, \, b0 e# y% C% xJUMP/l40:
9 y# b% v4 n7 O, A# ?, Ulab8:
/ `: ]0 w! \) _: D$ Q! ]MESSG/'五次多項式回程'
LRR:
IFTHEN/m<Angle3+2
$ p: {; u9 w9 a0 EJ(m)=m+Angle1+Angle2-1
7 b4 B: a4 A) OW=(J(m)-Angle1-Angle2)/Angle3
S(m)=h-h*(10*W*W*W-15*W*W*W*W+6*W*W*W*W*W)
& P7 m2 W; c! p/ N, q" s" z2 cX(m)=(R0+S(m))*cosf(J(m))
1 _; t3 x4 b. x1 S3 [Y(m)=(R0+S(m))*sinf(J(m))
Z=0
pt(m)=POINT/X(m),Y(m),Z
m=m+1
JUMP/LRR:
ENDIF
/ w  w6 |$ F( b4 A4 V* W- @spln(2)=SPLINE/pt(1..Angle3+1)
DELETE/pt(1..Angle3+1)
6 @& e- m2 U& cJUMP/l40:
- A8 _/ B  N$ A9 dlab9:
MESSG/'簡諧運動回程'
$ t$ S; t+ ~7 E3 |+ jLWW:
IFTHEN/m<Angle3+2
" z# O; N8 j$ g" E+ C) kJ(m)=m+Angle1+Angle2-1
S(m)=h*(1+cosf(180*(J(m)-Angle1-Angle2)/Angle3))/2
( W& h( g9 I4 f6 x1 l" V' hX(m)=(R0+S(m))*cosf(J(m))
  N1 E3 I4 ~6 a4 V6 U" J6 z2 pY(m)=(R0+S(m))*sinf(J(m))
Z=0
pt(m)=POINT/X(m),Y(m),Z
m=m+1
7 X' c$ k  H7 P% P1 m8 s% d3 A5 }JUMP/LWW:
$ g+ I; Z- N9 O# {( y+ XENDIF
spln(2)=SPLINE/pt(1..Angle3+1)
DELETE/pt(1..Angle3+1)
8 D! q) G$ w" X) I2 j- rJUMP/l40:
6 G0 m2 O0 B* z7 `" F, k9 H, klab10:
MESSG/'擺線運動回程'
) t* V7 N' d4 B6 qLQQ:
% n7 Y4 P/ j* XIFTHEN/m<Angle3+2
J(m)=m+Angle1+Angle2-1
A=J(m)-Angle1-Angle2
) e% P# o# e# s( I5 ES(m)=h*(1-A/Angle3+sinf(360*A/Angle3)/6.2832)
  E/ \' A; g( |' OX(m)=(R0+S(m))*cosf(J(m))
Y(m)=(R0+S(m))*sinf(J(m))
8 G- q4 o8 K4 d1 ^- [+ F1 D; hZ=0
7 t' ~: S/ n, T1 I. u# o$ T7 Jpt(m)=POINT/X(m),Y(m),Z
2 Y; C& t! [( u6 j% j- Xm=m+1
JUMP/LQQ:
0 t) y! J1 y/ b4 }- q' U' g; NENDIF
' T/ E( S: x& I- zspln(2)=SPLINE/pt(1..Angle3+1)
- j& o& {* u- h3 r8 U, R( Y1 nDELETE/pt(1..Angle3+1)
JUMP/l40:
l40:
$$遠休止角
4 N  ]/ q, L* {% ^( l, ~% LPT1=POINT/0,0
: i8 W: K) V4 k! rCR1=CIRCLE/CENTER,PT1,RADIUS,R0+h,START,Angle1,END,Angle1+Angle2
9 j/ X/ w+ u& V* Y: {; S$$近休止角
  n! ~; _) {! ~$ ]  o$ ^2 jCR2=CIRCLE/CENTER,PT1,RADIUS,R0,START,Angle1+Angle2+Angle3,END,0
JUMP/stop:
( O5 L: w) y. \stop:
halt

1 \8 }6 j* R! C7 f: P" _/ f
0 W6 Q- n& d& N& ?) C" s: I好多圖片不能上傳,，如有需要的話,。把郵箱給我，我可以發(fā)給他

78273928

[email protected]    不勝感激   

fewofj

回復 78273928 的帖子

4 `5 c" a/ j% T. p1 M7 v0 p馬上發(fā)給你,。 如果收不到可以QQ聯(lián)系我：532131146

78273928

回復 fewofj 的帖子
; o+ t# K3 C# M( c: e, W
謝謝 收到了  學習一下

xiaowuzh

回復 fewofj 的帖子

樓主我郵箱的[email protected],。發(fā)給我一份吧，謝謝,。
, H' e& B# o( b

zaq8577

謝謝,，正想了解一下 [email protected]

holland930

[email protected]  不勝感激 謝謝！