非圓齒輪二次開發(fā)

lijun1226

畫齒廓,，為什么最高點(diǎn)不在齒頂高那里,。感覺不對(duì),。大家能看看我的程序嗎,？Dim i As Integer
) U* c+ A( a- F' d3 f3 q9 T# `ReDim x0(18)
% V2 `1 o1 ~4 v& AReDim y0(18)

Dim k0 As Integer
9 R, O6 B* k+ ?& k9 [& OReDim p0(18)
$ N: M4 o) @) T0 q: f2 `# gReDim q0(18)
5 X: k8 X4 O8 }) {$ m
; _+ f1 ~* o: P3 r6 @, \Dim h0 As Integer
' N+ T, m: {7 X8 l% d  J, _ReDim p00(18)
ReDim q00(18)
3 O- E: Y5 U0 N0 s9 k# Q

u = Sqr((Da / Db) ^ 2 - 1)
g = u / 14
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1 s6 g* n  S$ M- u
xx = 0.5 * Da * Sin(Tan(f) - f)
yy = 0.5 * Da * Cos(Tan(f) - f)
( v$ F% f, `* {
( ^, L" ?( s% f1 E! K

( t0 c3 F! y! |5 x" y6 O; |. H6 u
# W. ~9 V5 \8 L' V( \s = pi * m / 2
inva = Tan(a) - a
sb = Cos(a) * (s + m * z * inva)
j = 2 * sb / Db
; b# h3 L$ k* d" i  t  T) O, B- X6 @
t = 0

3 r7 U3 e! }7 IFor i = 1 To 14

If t <= u Then

0 c* ^, T% T# [% M, s/ d- z7 u: kx0(i) = 0.5 * Db * Sin(t) - Db / 2 * t * Cos(t)
y0(i) = 0.5 * Db * Cos(t) + Db / 2 * t * Sin(t)

p00(i) = -0.5 * Db * Sin(t) + 0.5 * Db * t * Cos(t)
q00(i) = 0.5 * Db * Cos(t) + 0.5 * Db * t * Sin(t)

+ _+ O' L4 V/ dt = t + g
; U) U! l& }0 h( x) s
p0(i) = p00(i) * Cos(j) + q00(i) * Sin(j)
q0(i) = -p00(i) * Sin(j) + q00(i) * Cos(j)
End If
Next i

Part.SetPickMode
xx = 0
7 l: e# A) `+ w4 Q6 p+ ^8 cyy = 0.5 * Df
Xx1 = xx * Cos(j) + yy * Sin(j)
  m6 Z# {4 l$ v' ZYy1 = xx * Sin(j) + yy * Cos(j)

4 i) m- Q. l3 p  ?  V! g3 s  Lp000 = -0.5 * Db * Sin(0) + 0.5 * Db * 0 * Cos(0)
  Q. i, s8 `: Mq000 = 0.5 * Db * Cos(0) + 0.5 * Db * 0 * Sin(0)
0 q  p% G- P. R: v


Part.SketchSpline 13, 0.001 * x0(1), 0.001 * y0(1), 0
Part.SketchSpline 12, 0.001 * x0(2), 0.001 * y0(2), 0
' V5 M; L. p, b4 v4 jPart.SketchSpline 11, 0.001 * x0(3), 0.001 * y0(3), 0
, Z. D6 Y( v; [Part.SketchSpline 10, 0.001 * x0(4), 0.001 * y0(4), 0
* |) ]* `+ t. k% yPart.SketchSpline 9, 0.001 * x0(5), 0.001 * y0(5), 0
Part.SketchSpline 8, 0.001 * x0(6), 0.001 * y0(6), 0
Part.SketchSpline 7, 0.001 * x0(7), 0.001 * y0(7), 0
& Z! {$ f$ S: N
Part.SketchSpline 6, 0.001 * x0(8), 0.001 * y0(8), 0
; k3 X6 ]$ O) o& a# vPart.SketchSpline 5, 0.001 * x0(9), 0.001 * y0(9), 0
Part.SketchSpline 4, 0.001 * x0(10), 0.001 * y0(10), 0
" c0 a5 `+ U) x( M' |+ N& @Part.SketchSpline 3, 0.001 * x0(11), 0.001 * y0(11), 0
Part.SketchSpline 2, 0.001 * x0(12), 0.001 * y0(12), 0
Part.SketchSpline 1, 0.001 * x0(13), 0.001 * y0(13), 0
Part.SketchSpline 0, 0.001 * x0(14), 0.001 * y0(14), 0
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Part.SketchSpline 13, 0.001 * p0(1), 0.001 * q0(1), 0
/ ~. h5 u2 F, f- F' mPart.SketchSpline 12, 0.001 * p0(2), 0.001 * q0(2), 0
" Z/ n# Y& n5 a9 h( X$ A7 x5 nPart.SketchSpline 11, 0.001 * p0(3), 0.001 * q0(3), 0
" S' O  G+ f) D0 rPart.SketchSpline 10, 0.001 * p0(4), 0.001 * q0(4), 0
Part.SketchSpline 9, 0.001 * p0(5), 0.001 * q0(5), 0
4 n( c+ O% A6 B1 RPart.SketchSpline 8, 0.001 * p0(6), 0.001 * q0(6), 0
Part.SketchSpline 7, 0.001 * p0(7), 0.001 * q0(7), 0
/ r' I7 A! j( E# \$ O
8 U# a# }7 z& D* XPart.SketchSpline 6, 0.001 * p0(8), 0.001 * q0(8), 0
5 Q  K& ?! `" E( dPart.SketchSpline 5, 0.001 * p0(9), 0.001 * q0(9), 0
9 @) u! O- T3 P2 hPart.SketchSpline 4, 0.001 * p0(10), 0.001 * q0(10), 0
/ ?. E' k$ A2 w5 lPart.SketchSpline 3, 0.001 * p0(11), 0.001 * q0(11), 0
Part.SketchSpline 2, 0.001 * p0(12), 0.001 * q0(12), 0
) h( ^% m8 }" y% o% i! s  C3 ?Part.SketchSpline 1, 0.001 * p0(13), 0.001 * q0(13), 0
Part.SketchSpline 0, 0.001 * p0(14), 0.001 * q0(14), 0
% C* V# C: _8 R2 K0 g2 @. N
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George_W4TBo

是solidworks的二開嗎，真費(fèi)勁哥都比較擯棄,，這是最近做的一個(gè)單邊連續(xù),，單邊步進(jìn)機(jī)構(gòu)的其中一對(duì)非圓齒輪，在家里所以圖不多,，有空再更新，歡迎交流